1.) f(x) = ax^2 + bx + c
f(0) = 4
f '(-2) = 0
the point (4,20) lies on the function
Determine the values of a,b, and c
well, f(0) = c = 4, so that was easy
the slope is zero at x = -2
so 0 = 2 a x + b when x = -2
0 = 2 a(-2) + b
b = 4 a
so
y = a x^2 + 4 a x + 4
but we know y = 20 when x = 4
so
20 = a (16) + 16 a + 4
16 = 2 (16 a)
a = 1/2 etc
1.) f(x) = ax^2 + bx + c
f(0) = 4
f '(-2) = 0
the point (4,20) lies on the function
Determine the values of a,b, and c
2.) let y = √2+√2+√2+x. show that f '(2) = 1/64
Note : the y function is connected (no spaces in between the square roots).
2 answers
so, if you mean that
y = √(2+√(2+√(2+x)))
then
y' = 1/(8√(2+√(2+√(2+x))) √(2+√(2+x)) √(2+x))
Now jut plug in x=2
y = √(2+√(2+√(2+x)))
then
y' = 1/(8√(2+√(2+√(2+x))) √(2+√(2+x)) √(2+x))
Now jut plug in x=2