1. Determine the zeros of the quadratic function f(x)=(x+6)^2−9

Question

A. The zeros are (−3,0) and (−9,0)
B. The zeros are (0,−3) and (0,−9)
C. The zeros are (3,0) and (9,0)
D. The zeros are (3,0) and (−15,0)
2. 2(x−2)^2−2 is the vertex form of the quadratic function f(x). Does this function have a minimum or maximum value and what is it?
A. The function has a minimum value of -2.
B. The function has a minimum value of 2.
C. The function has a maximum value of -2.
D. The function has a maximum value of 2.
3. Let f(x)=a(x−h)^2+k. Where is the y-intercept of f(x)?
A. (0, ah^2+k)
B. (−ah^2+k, 0)
C. (ah^2+k, 0)
D. (0, −ah2+k)
aswer please

Answer 1

1. The zeros of the quadratic function f(x)=(x+6)^2-9 are (-3, 0) and (-9, 0). The correct answer is A.

2. The function 2(x-2)^2-2 does have a minimum value, which is -2. The correct answer is A.

3. The y-intercept of the function f(x)=a(x-h)^2+k is (0, ah^2+k). The correct answer is A.