3. SHOW YOUR WORK:
Using the Pythagorean Theorem, we can find the length of one side of Square C.
Let's call the length of one side of Square C "x".
The diagonal of Square C is 20 meters.
Using the Pythagorean Theorem, we have:
x^2 + x^2 = 20^2
2x^2 = 400
x^2 = 200
x = √200
x ≈ 14.14
The area of Square C is given by x^2:
Area = (14.14)^2
Area ≈ 200 acres
4. The areas of Square A and Square B are 16 acres and 9 acres respectively. The sum of these areas is 16 + 9 = 25 acres. This is less than the area of Square C which is approximately 200 acres.
1. Count the number of squares inside Field A. This is the area of Square A in acres. Write it below: (1 point)
Area = _____16____ acres
2. Count the number of squares inside Field B. This is the area of Square B in acres. Write it below: (1 point)
Area = ______9____ acres
3. SHOW YOUR WORK: Use the Pythagorean Theorem to find the area of Field C in acres: (2 points)
Area = ________ acres
4. Add your answers from 1 and 2 then compare the result with your answer to 3. How do they compare? (1 point)
3 answers
THAT MAKES NO SENCE I NEED YOU TO USE 16 A AND B 9 THE Pythagorean Theorem to find the area of Field C in acres THEN YOU . Add your answers from 1 and 2 then compare the result with your answer to 3. How do they compare?
I apologize for the confusion. Let's do the calculation again using the given values.
1. The number of squares inside Field A is 16.
Area of Square A = 16 acres.
2. The number of squares inside Field B is 9.
Area of Square B = 9 acres.
3. Let's find the area of Field C using the Pythagorean Theorem.
In Square C, one side is the hypotenuse and the other two sides are equal.
Let's call the length of one side of Square C "x".
Using the Pythagorean theorem, we have:
x^2 + x^2 = (20)^2
2x^2 = 400
x^2 = 200
x = √200
The area of Square C is given by x^2:
Area of Square C ≈ (√200)^2 ≈ 200 acres.
4. The sum of the areas of Square A and Square B is:
16 + 9 = 25 acres.
Comparing this with the area of Square C (which is approximately 200 acres), we can see that the sum of the areas of Square A and Square B (25 acres) is significantly smaller than the area of Square C.
1. The number of squares inside Field A is 16.
Area of Square A = 16 acres.
2. The number of squares inside Field B is 9.
Area of Square B = 9 acres.
3. Let's find the area of Field C using the Pythagorean Theorem.
In Square C, one side is the hypotenuse and the other two sides are equal.
Let's call the length of one side of Square C "x".
Using the Pythagorean theorem, we have:
x^2 + x^2 = (20)^2
2x^2 = 400
x^2 = 200
x = √200
The area of Square C is given by x^2:
Area of Square C ≈ (√200)^2 ≈ 200 acres.
4. The sum of the areas of Square A and Square B is:
16 + 9 = 25 acres.
Comparing this with the area of Square C (which is approximately 200 acres), we can see that the sum of the areas of Square A and Square B (25 acres) is significantly smaller than the area of Square C.