1.) cot(-θ)(secθ)

I think the answer is secθ but I don't know how to get this.

2.) (tanθ) / (cos)(90° -θ)

3.) 3sin2xcos2x - sin4x

4.) (cosx + tanx) / (csc^2 x)

1 answer

cot(-θ)(secθ)
= cos(-Ø)/sin(-Ø)(1/cosØ
= (cosØ/-sinØ)(1/cosØ
= - 1/sinØ
= - csc(Ø)

(test your answers with some weird angle, don't use 30's , 60's, or 45's)

2. you will have to know that
cos(90°-x) = sinx
take it from there

3. 3sin2xcos2x - sin4x
= 3sin2xcos2x - 2sin2xcos2x
= sin2xcos2x
or (1/2)sin4x

4. change everything to sines and cosines and just mess around with it.

make sure to test your answer vs the original with some strange angle on your calculator.
Similar Questions
  1. Verify the given equations:____1______ + ____1_______ = -2 tanθ tanθ – secθ tanθ + secθ 1 – sinθ = sec2θ – 2 secθ
    1. answers icon 1 answer
    1. answers icon 1 answer
  2. prove this identity:secθ +1/tanθ = tanθ/secθ −1
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions