John, you work all of these stoichiometry problems with 3 or 4 steps.
1. Write and balance the equation.
2. Convert what you have to mols. There are a couple of ways to do this.
a. If you have grams, then mols = grams/molar mass.
b. If you have a solution, then mols = M x L = ?
3. Use the coefficients in the balanced equation to convert mols of what you have to mols of what you want.
4. Then you convert mols of what you want (the product in most cases) to either (usually)
a. grams or
b. volume
If grams, then grams = mols x molar mass
If volume, then mols x 22.4L/mol if at STP or use PV = nRT if other than standard conditions are given.
With those steps you can work about 98% of the stoichiometry problems but I'm not about to do your test for you. That is cheating and you can't go through life cheating although some get by with it longer than others.
1.Cell respiration glucose is reacted wth oxygen in body to produce carbon dioxide and water how many liters of carbon dioxide would be produced if 90.0 g of glucose completely reacts with oxygen
C6H12O6(s)+ 6O2(g) -> 6H2O(g) + 6CO2 (g)
How many liters of carbon dioxide would be produced if 90.0 g of glucose completely reacts with oxygen
Show Work
A.11.2L B.21.99L. C.67.1L. D.131.9L.
2. How many liters of chlorine as can be produced when 1.96 L of HCl react with excess O2 at STP
4HCl(g)+O2(g)->2 Cl(g)+ 2H2O(l)
A.0.49 B. 0.98L. C. 1.96 L D. 3.92 L
Show work
3.The decomposition of potassium chlorate gives oxygen gas according to the reaction:
2 KClO3(s) -> 2KCl(s)+3O2(g)
How many grams KClO3 are needed to produce 10.0 L of O2 at STP
A. 18.2g. B.25.5g. C.36.5g. D.54.7g
1 answer
1 answer