Sketch in the height, now you have a right-angled triangle with hypotenuse 8 and base of 4
h^2 + 4^2 = 8^2
h^2 = 48
h = √48
area = (1/2)base x height
= (1/2)(4)√48 = .....
3. If you have a right-angled triangle , use Pythagoras to find the missing side.
then you have the base and the height
1. can you tell me how to find the area of an equilateral triangle ? its sides are all 8 . .
3. i guess this is a right triangle . . how to find its area and perimeter if one side is missing ? tell me please?
i want to know thank you so much
1 answer