1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN.

Question

ANS= MPa (Round to 3 decimal places)
Diameter = 33.000mm = 0.033m
30.000kN = 30000N

Area = pi*d^2/4
= 3.1416 * 0.033^2/ 4
= 3.1416 *0.001089/ 4
= 0.0034212024/ 4
= 8.553006*10^-4
= 0.0008553
Stress= Load/Area
= 30000/ 0.0008553
= 35075412.14Pa
= 35075.41214kPa
ANS = 35.07541214MPa

2) Consider that the rod was originally 1.000 meters long, and it was stretched 1.110mm by the pulling force. Calculate the strain produced in the rod.
ANS=(6decimal places)
1.110mm = 0.00111m
= 0.00111m/1m
ANS = 0.001110
Please check. Thank you.

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