1. Calcium carbonate reacts with HCl according to the following equation:

Question

2HCl(aq)+CaCO3(s)→CaCl2(aq)+H2O(l)+CO2(g)
How many moles of HCl are in 65 mL of 0.15 M HCl?

2. What mass of calcium carbonate is needed for complete reaction with the HCl in (a)?

Answer 1

moles=.15M*.065L= ????

you need half that number of moles of CaCO3

massCaCO3=1/2 (.15*.065)*formulamassCaCO3