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Calcium carbonate reacts with HCl according to the following equation: 2HCl(aq)+CaCO3(s)→CaCl2(aq)+H2O(l)+CO2(g) How many moles...Asked by Dhan Rai
1. Calcium carbonate reacts with HCl according to the following equation:
2HCl(aq)+CaCO3(s)→CaCl2(aq)+H2O(l)+CO2(g)
How many moles of HCl are in 65 mL of 0.15 M HCl?
2. What mass of calcium carbonate is needed for complete reaction with the HCl in (a)?
2HCl(aq)+CaCO3(s)→CaCl2(aq)+H2O(l)+CO2(g)
How many moles of HCl are in 65 mL of 0.15 M HCl?
2. What mass of calcium carbonate is needed for complete reaction with the HCl in (a)?
Answers
Answered by
bobpursley
moles=.15M*.065L= ????
you need half that number of moles of CaCO3
massCaCO3=1/2 (.15*.065)*formulamassCaCO3
you need half that number of moles of CaCO3
massCaCO3=1/2 (.15*.065)*formulamassCaCO3
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