These questions are not about algebra. They are about probability.
1) Correct: 31x10x2
2) There are 9 choices for the first digit, 8 for the second, etc. The answer is 9*8*7*6*5 = 9!/4!
You chose incorrectly. Were you just guessing?
3) Wrong. 7*6*5*4*3 = ?
4) No. What did you choose D? A wild guess perhaps? I suggest you review the definition of "Combinations" and use the appropriate formula.
5) Wrong again. When stating odds, the ratio of the first number to the sum of both numbers is the probability the first event will occur.
1)An ice cream store has 31 flavors of ice cream and 10 toppings. A regular sundae has 1 flavor of ice cream, 1 topping, and comes with or without whipped cream. How many different ice cream sundaes can be ordered?
A)310
B)372
C)620
D)82
I chose C
2)How many 5 digit codes are possible if 0 cannot be used and no digit can be repeated?
A)15,120
B)45
C)30,240
D)59,049
I chose B
3)A clown has 7 balloons, each a different color. There are 5 children. how many ways can the clown give each child a balloon?
A)21
B)5040
C)42
D)2520
I chose B
4)Evaluate C(13,9)
A)17,160
B)715
C)259,459,200
D)117
I chose D
5)The probabilty that an event will occur is 11/15. What are the odds that the event will occur?
A)15:11
B)11:15
C)4:1
D)11:4
I chose B
6 answers
Here is a popular web site about combinations and permutations. I suggest you review it, and use it for question 4)
http://mathforum.org/dr.math/faq/faq.comb.perm.html
http://mathforum.org/dr.math/faq/faq.comb.perm.html
thanks for the help. none were wild guesses
I don't understand what you said for #5 but its either C or D.
4 B) 5 D)
Lemme eat that little as s
6 answers