1) An equation of the line contains points (7/9, 7) and (-7/9) is

Question

2) Find the slope of the line tangent to the curve y=x^2 at the point (-0.6, 0.36) and find the corresponding equation of the tangent line

Answer 1

#1 I only see one point and a number.

#2 at the given point, the slope is -1.2
So, the line there is

y-0.36 = -1.2(x+0.6)