Asked by Henry
1. An airplane flies 200 km on course 110 degrees from point A to point B. At point B the pilot changes course to 37 degrees. The plane then flies 100 km to point C. Find the magnitude of the net displacement from A to C.
2. A plane is flying on a bearing of 25 degrees west of north at 530 mph. Express the velocity of the plane as a vector.
2. A plane is flying on a bearing of 25 degrees west of north at 530 mph. Express the velocity of the plane as a vector.
Answers
Answered by
Henry
1. AB+BC = 200km[110o] + 100km[37o]
X = 200*cos110 + 100*cos37 = 11.46 km.
Y = 200*sin110 + 100*sin37 = 248.1 km.
D^2 = X^2 + Y^2 = (11.46)^2+(248.1)^2 =
61,685
D = 248.4 km
2. V = 530mph[N25oW] = 530mph[115o] CCW.
X = 200*cos110 + 100*cos37 = 11.46 km.
Y = 200*sin110 + 100*sin37 = 248.1 km.
D^2 = X^2 + Y^2 = (11.46)^2+(248.1)^2 =
61,685
D = 248.4 km
2. V = 530mph[N25oW] = 530mph[115o] CCW.
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