HCl + KOH ==> KCl + H2O
millimiles HCl = mL x M = 33.0 mL x 1.0 M = 33.0
It takes 1 mol KOH to neutralize 1 mol HCl; therefore, moles KOH = moles HCl.
Then M KOH = millimoles/mL = 33.0/28.0 = ? M
1. A volume of 33.0 ml of 1.0 M Hydrochloric acid (HCI)
neutralizes a 28.0 ml sample of Potassium hydroxide
(KOH) solution. What is the concentration of KOH?
HCI + KOH → KCI + H₂O
1 answer
1 answer