The height from which the block was dropped, which is H above the compressed spring, satisfies the condition
gravitional P.E. lost = spring P.E. gained
M g H = (1/2) k X^2
They tell you what k, M and X are. Solve for H.
1.) A vertical spring with a spring constant of 450 N/m is mounted on the floor. From directly above the spring, which is unstrained, a 0.30 kg block is dropped from rest. It collides with and sticks to the spring, which is compressed 2.5 cm in bringing the block to a momentary halt. Air resistance neglible, from what height above the compressed string was the block dropped?
(Steps please?
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