Asked by John Gomez


1. A spring bearing a 10-pound weight has stretched 0.5 inches. If you were to increase the weight to 15 pounds, how many inches would the spring stretch?
Answered by Damon
F = k x

10 = k (.5)
k = 20 lb/in

15 = 20 x
x = 0.75 in
Answered by Daniel
10 = k (.5)
Answer
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