F = k x
10 = k (.5)
k = 20 lb/in
15 = 20 x
x = 0.75 in
1. A spring bearing a 10-pound weight has stretched 0.5 inches. If you were to increase the weight to 15 pounds, how many inches would the spring stretch?
3 answers
10 = k (.5)
The heck is a clown bot
1 answer