6Fe^2+ + Cr2O7^2- + 14H^+ ==> 2Cr^3+ + 6Fe^3+ + 7H2O
millimoles K2Cr2O7 = mL x M = 60.00 x 0.01 = 0.6000
Convert to mmoles Fe that is 0.6000 x (6 mols FeSO4/1 mol K2Cr2O7) = 3.6
Then M FeSO4 = mmols/mL = ?
You should add the zeros and watch the number of significant figures.
1. A solution of 0.010 M K2Cr2O7 with a volume of 60.00 mL reacts in a titration reaction
with 20.00 mL of FeSO4 in sulphuric acid. Calculate the normality of FeSO4. 6Fe
2+ + Cr2O7
2- + 14 H
1 answer