1) A particle is moving with acceleration a(t)=36t+10. its position at time t=0 is s(0)=16 and its velocity at time t=0 is v(0)=9. What is its position at time t=11?

Answer 1

a(t) = 36t+10

v(t) = 18t^2+10t+c
v(0)=9, so c=9 and
v(t) = 18t^2+10t+9

s(t) = 6t^3+5t^2+9t+c
s(0) = 16, so c=16 and
s(t) = 6t^3+5t^2+9t+16

So, find s(11)