3. d = V*T = 40 km
V*2 = 40
V = 20 km/h
4. Fr = 100N[170o] + 100N[50o]
X = 100*Cos170 + 100*Cos50 = -34.2 N.
Y = 100*sin170 + 100*sin50 = 94 N.
Q2.
Tan A = Y/X = 94/-34.2 = -2.74854
A = -70o = 70o N. of W. = 110o CCW
Fr = Y/sin A = 94/sin110 =
5. Fap*CosA-Fk = M*a
Fap = 40 N.
A = 37o
Fk = Force of kinetic friction.
M = 5 kg
a = 3 m/s^2
Solve for Fk
1. A monkey in a perch 20 m high in a tree drops a coconut above the head of a zoo keeper as he runs with a speed 1.5 m/s beneath the tree actually intending to hit the toes of the zoo keeper, how early in seconds should the coconut be dropped by the monkey.
2 A monkey in a perch 20 m high in a tree drops a coconut above the head of a zoo keeper as he runs with a speed 1.5 m/s beneath the tree. How far behind him in meters does the coconut hit the ground.
3. A man leaves the garrage in the house and drive to a neighboring town which is twenty km away from his house on sight-seeing. He return home to his garrage two hours after. What is his average velocity from his home in km/h?
4. Two force act a point object as follows: 100 N at 170 degree and 100 N at 50 degree. Find the resultant force.
5. A 40 N force applied at an angle of 37 degree above the horizontal pulls a 5-kg box on a horizontal floor. The acceleration of the box is 3m/s square. How large a frictional force must be retarding the motion of the box?
1 answer