A long strip of copper 8 inches wide is to be made into a rain gutter by turning up the sides to form a trough with a rectangular cross section. Find the dimentions of the cross-section if the carrying capacity of the trough is to be a maximum.
If x = the width, then the height y = (8 - x)/2
The volume of the crossection is therefore V = x(8 - x)/2 = 4x - x^2/2
Setting the first derivitive dv/dx = 4 - x = 0, x = 4 making y = 2
2. A sheet of cardboard 18 in square is used to make an open box by cutting squares of equal size from the corners and folding up the sides. What size squares should be cut to obtain a box with largest possible volume?
If the squares are x by x, the volume becomes V - (18 - 2x)(18 - 2x)
Can you take it from here?
1. A long strip of copper 8 inches wide is to be made into a rain gutter by turning up the sides to form a trough with a rectangular cross section. Find the dimentions of the cross-section if the carrying capacity of the trough is to be a maximum.
2. A sheet of cardboard 18 in square is used to make an open box by cutting squares of equal size from the corners and folding up the sides. What size squares should be cut to obtain a box with largest possible volume?
Please help! Thank you!
2 answers
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