1. A chemistry student added 22.5 grams of aluminum at 85.00C to 115 grams of water at 23.00C in a perfect calorimeter. The final temperature of the aluminum-water mixture was 41.40C. Use the student’s data to calculate the specific heat of aluminum in joules/gram0C.

Question

2. Calculate the final temperature that results from mixing 100.0 grams of water at 1000C with 106.0 grams of water at 24.80C

Answer 1

[mass Al x specific heat Al x (Tfinal - Tinitial)] + [mass H2O x specific heat H2O x (Tfinal - Tinitial)] = 0

[22.5 g Al x sp. h. Al x (41.40 - 85.00)] + [115 x sp.h. H2O x (41.40 - 23.00)] = 0
You will need to look up the specific heat (sp.h.) of water.
The second problem is done the same way.