1.

A camera manufacturer spends $1,800 each day for overhead expenses plus $9 per camera for labor and materials. The cameras sell for $18 each.
a. How many cameras must the company sell in one day to equal its daily costs?
b. If the manufacturer can increase production by 50 cameras per day, what would their daily profit be?

1 answer

To determine how many cameras the company must sell to equal its daily costs, let's first calculate the total daily costs.

Given:

  • Daily overhead costs = $1,800
  • Cost per camera (labor and materials) = $9
  • Selling price per camera = $18

Part a: Calculate the number of cameras to break even

Let \( x \) be the number of cameras sold in one day.

The total daily costs can be determined as follows: \[ \text{Total Costs} = \text{Overhead Costs} + \text{Cost per Camera} \times \text{Number of Cameras} \] \[ \text{Total Costs} = 1,800 + 9x \]

The total revenue from selling \( x \) cameras is: \[ \text{Total Revenue} = \text{Selling Price per Camera} \times \text{Number of Cameras} \] \[ \text{Total Revenue} = 18x \]

To find the break-even point, we set the total costs equal to the total revenue: \[ 1,800 + 9x = 18x \]

Now, solve for \( x \): \[ 1,800 = 18x - 9x \] \[ 1,800 = 9x \] \[ x = \frac{1,800}{9} = 200 \]

Answer to part a: The company must sell 200 cameras in one day to equal its daily costs.

Part b: Calculate the daily profit if production is increased

If the manufacturer can increase production by 50 cameras, the new number of cameras sold per day will be: \[ x + 50 = 200 + 50 = 250 \]

Now we will calculate the total revenue and total costs for the sale of 250 cameras.

Total Revenue for 250 cameras: \[ \text{Total Revenue} = 18 \times 250 = 4,500 \]

Total Costs for 250 cameras: \[ \text{Total Costs} = 1,800 + 9 \times 250 \] \[ \text{Total Costs} = 1,800 + 2,250 = 4,050 \]

Daily Profit can be calculated as: \[ \text{Profit} = \text{Total Revenue} - \text{Total Costs} \] \[ \text{Profit} = 4,500 - 4,050 = 450 \]

Answer to part b: Their daily profit would be $450.