number of 25 rupees tickets ---x
number of 30 rupees tickets --- 40-x
25x + 30(40-x) = 1125
solve for x
#2
John ---x
Babita -- 3x
Ahmed ---5(3x) = 15x
so ......
1.a bus is carrying 40 passengers some with 25 rupees ticket and the remaining with 30 rupees ticket. if the total amount collected from these passengers is 1125 rupees. find the number of passengers who have taken 25 rupees ticket
2.divide AED 1380 among Ahmed John and Babita so that the amount Ahmed receives is 5 times as much as babita's share and its 3 times as much as John's share
3 answers
Answer 1:
x + y = 40 (X by -25 for elimination)
25x + 30y = 1125
-25x - 25y = -1000
25x + 30y = 1125
___________________
5y = 125
y = 25 (plug in for y to find x)
x + 25 = 40
x = 40 - 25
x = 15
total number of passengers that bought 25 rupees ticket = 15
x + y = 40 (X by -25 for elimination)
25x + 30y = 1125
-25x - 25y = -1000
25x + 30y = 1125
___________________
5y = 125
y = 25 (plug in for y to find x)
x + 25 = 40
x = 40 - 25
x = 15
total number of passengers that bought 25 rupees ticket = 15
thank you REINY