CH3COONa = NaAc = base
CH3COOH = HAc = acid
(NaAc) = 0.56 g/molar mass/1L
(HAc) = 0.02 M from the problem. Post your work if you get stuck.
1) A buffer solution was made by adding 6.56g of sodium ethanoate to 1dm3 of 0.02moldm-3 ethanoic acid.
a) What is the concentration of the sodium ethanoate?
b)What is the concentration of the ethanoic acid?
2 answers
Wouldn't the concentration for CH3COONa be:
6.56 g /82 gmol-1 /1.00656 L
6.56 g /82 gmol-1 /1.00656 L