1) A bartender slides a beer mug at 1.4 m/s towards a customer at the end of a frictionless bar that is 1.8 m tall. The customer makes a grab for the mug and misses, and the mug sails off the end of the bar.

Question

(a) How far away from the end of the bar does the mug hit the floor?
0.849m
Just confused on part b)
(b) What are the speed and direction of the mug at impact?
Speed
Direction (below the horizontal)

2) Suppose the ball is thrown from the same height as in the PRACTICE IT problem (45.0m) at an angle of 32.0° below the horizontal. If it strikes the ground 43.8 m away, find the following. (Hint: For part (a), use the equation for the x-displacement to eliminate v0t from the equation for the y-displacement.)
(b) the initial speed (m/s)

(c) the speed and angle of the velocity vector with respect to the horizontal at impact
speed (m/s)
angle (° below the horizontal)

Answer 1

1a. h = 0.5*g*t^2 s.= 1.8.
0.5*9.8*t^2 = 1.8,
t = 0.61 s. = Fall time.
d = V * t = 1.4 * 0.61 =
=
1b. Y^2 = Yo^2 + 2g*h = 0 + 19,6*1,8 = 35.3,
Y = 5.94 m/s.

V = sqrt(1,4^2 + 5.94^2) =
Tan A = Y/X = 5.94/1.4
A =