Asked by KK
1. A ball is shot straight up into the air from the ground. It has a position function given by
𝑠(𝑡) = −16𝑡^2 + 64𝑡, where s(t) is measured in feet and t is time in seconds.
(𝑎) Find the average velocity of the ball for the time period beginning at t = 1 second
and lasting
(i) .5 seconds (ii) .1 seconds (iii) .05 seconds ( iv) .01 seconds
I was able to get s(1)= 48ft. Average Velocity: (I) 24 ft/sec, (II) 30.4 ft/sec, (III) 31.2 ft/sec, (IV) 31.84
Just wanted to make sure my answers are correct
𝑠(𝑡) = −16𝑡^2 + 64𝑡, where s(t) is measured in feet and t is time in seconds.
(𝑎) Find the average velocity of the ball for the time period beginning at t = 1 second
and lasting
(i) .5 seconds (ii) .1 seconds (iii) .05 seconds ( iv) .01 seconds
I was able to get s(1)= 48ft. Average Velocity: (I) 24 ft/sec, (II) 30.4 ft/sec, (III) 31.2 ft/sec, (IV) 31.84
Just wanted to make sure my answers are correct
Answers
Answered by
R_scott
looks good
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