1. M1 = 601 kg, V1 = 0.
M2 = 1880 kg, V2 = 14.5 m/s.
M1*V1+M2*V2 = M1*V3+M2*V4.
601*0+1880*14.5 = 601*V3+1880*V4,
Eq1: 601V3+1880V4 = 27,260,
V3 = ((M1-M2)V1 + 2M2*V2)/(M1+M2).
V3 = ((601-1880)0 + 3760*14.5)/(601+1880) = 54,520/2481 = 22 m/s.
In Eq1, replace V3 with 22 and solve for V4.
1. A 601 kg car stopped at an intersection is rear-ended by a 1880 kg truck moving with a speed of 14.5 m/s. If the car was in neutral and its brakes were off, so that the collision is approximately elastic, find the final speed of both vehicles after the collision.
_____________m/s (car)
_____________m/s (truck)
2.An explosion breaks an object into two pieces, one of which has 1.80 times the mass of the other. If 7800 J were released in the explosion, how much kinetic energy did each piece acquire?
heavier piece
_________J
lighter piece
____________ J
1 answer
2 answers