1. A 5 kg box is sitting at rest on a perfectly frictionless surface. Suddenly, a 100 N forces pulls it

eastward. Find the acceleration of the box.

1 answer

To find the acceleration of the box, we can use Newton's second law of motion, which states:

\[ F = ma \]

where:

  • \( F \) is the net force acting on the object,
  • \( m \) is the mass of the object,
  • \( a \) is the acceleration of the object.

In this case:

  • The force (\( F \)) applied to the box is 100 N (eastward).
  • The mass (\( m \)) of the box is 5 kg.

We can rearrange the equation to solve for acceleration (\( a \)):

\[ a = \frac{F}{m} \]

Substituting the known values:

\[ a = \frac{100 , \text{N}}{5 , \text{kg}} = 20 , \text{m/s}^2 \]

Therefore, the acceleration of the box is \( 20 , \text{m/s}^2 \) eastward.