rampheight/ramplength= tanTheta
solve for ramplength
ramplength= ctnTheta *rampheight.
and of course, height from
mgh=energy.
1.) a 5.0 kg stone slid up a frictionless ramp that has an incline of 25 degree. How long is the ramp if gravitational potential energy associated with the stone is 2.4 x 10^2 J.
2.) A pogo stick contains a spring with a constant force of 1.5 x 10^4 N/m. Suppose the elastic potential energy stored in the spring as the pogo stick is pushed downward is 120 J. how far is the spring compressed?
2 answers
GPE =mgh
240 =5x10xheight
height =240/50
height =4.8m
Sin 25 =4.8/hypotenuse
since hypotenuse is the length of the ramp it can be found from above.
240 =5x10xheight
height =240/50
height =4.8m
Sin 25 =4.8/hypotenuse
since hypotenuse is the length of the ramp it can be found from above.
2 answers