For #1 you didn't list the choices.
190 = 4.51 x Z x (315.7-21.3) and solve for Z.
For #2, your numbers are ok but you have too many significant figures.
1. A 4.61 g sample of one of the substances listed in the table below was heated from 21.3°C to 315.7°C, requiring 190 J to do so. What substance was heated?
I got mercury(l)
2. Calculate the energy required in joules and calories to heat 33.9 g of aluminum from 30.7°C to 42.8°C. (shc of aluminum is 0.89 j/g C)
What i got:
cal = 87.253609
joule = 365.0691
1 answer
1 answer