1.9 moles of Ar and 2.5 moles of Ne are added to a 10.0 L container at 20.0oC. What will the internal pressure (atm) be?

Question

1.9 moles of Ar and 2.5 moles of Ne are added to a 10.0 L container at 20.0oC.  What will the internal pressure (atm) be?

DrBob222 · Answer

Use PV = nRT with n = 1.9+2.5 = ?

Anonymous · Answer

10.58 atm