1.8 mol HCl and 3.3 mol NaOH react accord- ing to the equation
HCl + NaOH −→ NaCl + H2O .
Calculate the amount in moles of NaCl formed.
Answer in units of mol.
1.8 mol HCl and 3.3 mol NaOH react according to the equation
3 answers
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www.jiskha.com/questions/674647/1-9-mol-hcl-and-3-8-mol-naoh-react-according-to-the-equation-hcl-naoh-nacl-h2o
www.jiskha.com/questions/674647/1-9-mol-hcl-and-3-8-mol-naoh-react-according-to-the-equation-hcl-naoh-nacl-h2o
This is a limiting reagent (LR) problem. You know you have a LR problem when an amount for more than one reactant is given.
HCl + NaOH −→ NaCl + H2O .
Use the coefficients to tell you the following:
1.8 mols HCl will form 1.8 mols NaCl given an excess of NaOH.
3.3 mols NaOH will form 3.3 mols NaCl given an excess of HCl.
Of those two scenarios you will form 1.8 mols NaCl; i.e., the smaller amount of substance formed is always the winner in LR problems.
HCl + NaOH −→ NaCl + H2O .
Use the coefficients to tell you the following:
1.8 mols HCl will form 1.8 mols NaCl given an excess of NaOH.
3.3 mols NaOH will form 3.3 mols NaCl given an excess of HCl.
Of those two scenarios you will form 1.8 mols NaCl; i.e., the smaller amount of substance formed is always the winner in LR problems.