1.62 g of CoCl2 x (xH20) were heated. After heating only .88g of CoCl2 remained. What was the formula of the original hydrate?

Answer 1

CoCl2 = 0.88 g
H2O = 1.62-0.88 = 0.74 g

Convert to moles.
moles CoCl2 = 0.88/molar mass
moles H2O = 0.74/molar mass.

Now find the ratio of moles H2O to one(1) mole CoCl2. The easy way to do that is to divide moles CoCl2 by itself, then divide the moles H2O by the same small number and round to a whole number.

Answer 2

.46%

Answer 3

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