To determine whether (1, 6) is a solution to the equations \( -x + y = 5 \) and \( y = (x - 3)^2 + 2 \), we can substitute \( x = 1 \) and \( y = 6 \) into both equations.
-
For the first equation \( -x + y = 5 \): \[ -1 + 6 = 5 \ 5 = 5 \] This equation is true.
-
For the second equation \( y = (x - 3)^2 + 2 \): \[ 6 = (1 - 3)^2 + 2 \ 6 = (-2)^2 + 2 \ 6 = 4 + 2 \ 6 = 6 \] This equation is also true.
Since (1, 6) satisfies both equations, the statement is:
True