heat lost by water = heat gained by unknown
your method is fine
1.5 kg of an unknown liquid at a temperature of 17 degrees Celsius is added to 2kg of water at 50C. The final temp of the mixture is 45C. Assuming no heat is lost to the environment, determine the specific heat capacity of the unknown liquid.
So I assume you would do
Qmct = qmct
And then solve for the q of the unknown and then plug the q into the specific latent formula and solve for the lf? I don't think that's right though, I'm not sure. I would really appreciate the help!
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