Once you have simplified the expression to \( s - 3 \), the next steps depend on the context of the problem or the specific goal you have. Here are a few possibilities: 1. **Solving an Equation**: If you are solving an equation where \( s - 3 = 0 \), you would add 3 to both sides to find: \[ s = 3 \] 2. **Substituting Values**: If you need to evaluate \( s - 3 \) for a specific value of \( s \), you would substitute that value into the expression. 3. **Further Manipulation**: If you need to manipulate the expression further (for example, setting it equal to another expression or factor it), you would proceed accordingly. 4. **Graphing or Analyzing**: If you're looking to graph \( y = s - 3 \), you would note that it’s a linear function with a slope of 1 and a y-intercept at -3. Please provide more context if you have a specific goal in mind!

It seems like you might want to simplify or work with the numbers \(-2\) and \(-10\). Here are a few operations you could perform with these numbers: 1. **Addition**: \[ -2 + (-10) = -2 - 10 = -12 \] 2. **Subtraction**: \[ -2 - (-10) = -2 + 10 = 8 \] \[ -10 - (-2) = -10 + 2 = -8 \] 3. **Multiplication**: \[ -2 \times -10 = 20 \] 4. **Division**: \[ -2 \div -10 = \frac{2}{10} = \frac{1}{5} \] \[ -10 \div -2 = 5 \] If you want to perform a specific operation with \(-2\) and \(-10\) or if there's additional context or a question you have in mind, please let me know!

1/5(5s - 15)

To simplify the expression \( \frac{1}{5}(5s - 15) \), you can distribute \(\frac{1}{5}\) to each term inside the parentheses:

\[ \frac{1}{5}(5s) - \frac{1}{5}(15) \]

Calculating each term gives:

\[ s - 3 \]

So, the simplified expression is:

\[ s - 3 \]

After that what do we do?

Once you have simplified the expression to \( s - 3 \), the next steps depend on the context of the problem or the specific goal you have.

Here are a few possibilities:

Solving an Equation: If you are solving an equation where \( s - 3 = 0 \), you would add 3 to both sides to find: \[ s = 3 \]
Substituting Values: If you need to evaluate \( s - 3 \) for a specific value of \( s \), you would substitute that value into the expression.
Further Manipulation: If you need to manipulate the expression further (for example, setting it equal to another expression or factor it), you would proceed accordingly.
Graphing or Analyzing: If you're looking to graph \( y = s - 3 \), you would note that it’s a linear function with a slope of 1 and a y-intercept at -3.

Please provide more context if you have a specific goal in mind!

1/4(12w - 8)

To simplify the expression \( \frac{1}{4}(12w - 8) \), you can distribute \( \frac{1}{4} \) to each term inside the parentheses:

\[ \frac{1}{4}(12w) - \frac{1}{4}(8) \]

Calculating each term gives:

\[ 3w - 2 \]

So, the simplified expression is:

\[ 3w - 2 \]

If you have any further steps in mind or a specific question related to this expression, feel free to ask!

-2
-10

It seems like you might want to simplify or work with the numbers \(-2\) and \(-10\). Here are a few operations you could perform with these numbers:

Addition: \[ -2 + (-10) = -2 - 10 = -12 \]
Subtraction: \[ -2 - (-10) = -2 + 10 = 8 \] \[ -10 - (-2) = -10 + 2 = -8 \]
Multiplication: \[ -2 \times -10 = 20 \]
Division: \[ -2 \div -10 = \frac{2}{10} = \frac{1}{5} \] \[ -10 \div -2 = 5 \]

If you want to perform a specific operation with \(-2\) and \(-10\) or if there's additional context or a question you have in mind, please let me know!

-12 = 6w
What does w equal

To solve the equation \(-12 = 6w\) for \(w\), you can divide both sides of the equation by \(6\):

\[ w = \frac{-12}{6} \]

Now, simplify the right side:

\[ w = -2 \]

Thus, the solution is:

\[ w = -2 \]

F + 15
- 2/3f

It looks like you have an expression involving \( F \) and \( f \). The expression you provided can be interpreted as:

\[ F + 15 - \frac{2}{3}f \]

To combine or simplify this expression further, it’s essential to clarify a few things:

If \( F \) and \( f \) are the same variable: In that case, you would replace \( F \) with \( f \) (or vice versa) and combine like terms.
- Assuming \( F = f \): \[ f + 15 - \frac{2}{3}f \]
- Combine the \( f \) terms: \[ \left(1 - \frac{2}{3}\right)f + 15 = \frac{1}{3}f + 15 \]
If \( F \) and \( f \) are different variables: Then the expression stays as is: \[ F + 15 - \frac{2}{3}f \]

If you have specific instructions or additional context about what you're trying to achieve with this expression, please let me know!