1.43.4 kcal of heat is required to decompose 2 mole of mecury(II) oxide according to the equation 2HgO(s)➡2Hg(l) + O⬇2(g) . What quantity of energy is required to decompose 10.8g of HgO ? (Hg=200.59, O=16)

Question

1.43.4 kcal of heat is required to decompose 2 mole of mecury(II) oxide according to the equation                          2HgO(s)➡2Hg(l) + O⬇2(g) . What  quantity of energy is required to decompose 10.8g of HgO ? (Hg=200.59, O=16)

DrBob222 · Answer

Is that question 1 which says 43.4 kcal or some other notation. If I have interpreted this correctly, then
1 mol HgO is (216.6) so 2 mols = 2*216.6. You have 10.8 g; therefore,
43.4 Kcal x [10.8/(2*216.6)] = ?

daniel · Answer

2.17kcal