1/4 of morolake age nine years ago is the same as 1/5 of her age next year.

How old is morolake now?

1 answer

Let's denote Morolake's current age as \( x \).

Nine years ago, Morolake's age was \( x - 9 \). According to the problem, \( \frac{1}{4} \) of her age nine years ago is equal to \( \frac{1}{5} \) of her age next year. Next year, Morolake's age will be \( x + 1 \).

Setting up the equation based on the information given:

\[ \frac{1}{4}(x - 9) = \frac{1}{5}(x + 1) \]

Now we can eliminate the fractions by multiplying both sides by 20 (the least common multiple of 4 and 5):

\[ 20 \cdot \frac{1}{4}(x - 9) = 20 \cdot \frac{1}{5}(x + 1) \]

This simplifies to:

\[ 5(x - 9) = 4(x + 1) \]

Expanding both sides:

\[ 5x - 45 = 4x + 4 \]

Now, subtract \( 4x \) from both sides:

\[ 5x - 4x - 45 = 4 \] \[ x - 45 = 4 \]

Next, add 45 to both sides:

\[ x = 49 \]

Thus, Morolake is currently \( \boxed{49} \) years old.

To verify:

  • Nine years ago, Morolake was \( 49 - 9 = 40 \).
  • Next year, her age will be \( 49 + 1 = 50 \).

Calculating the values:

  • \( \frac{1}{4} \) of 40 is \( 10 \).
  • \( \frac{1}{5} \) of 50 is \( 10 \).

Both sides are equal, confirming the solution is correct. Morolake is indeed \( \boxed{49} \) years old.