1.38 mol HCl and 2.9 mol NaOH react accord-

Question

ing to the equation
HCl + NaOH −→ NaCl + H2O .
If the limiting reactant is HCl, determine
the amount of excess reactant that remains.
Answer in units of mol.

Answer 1

mol HCl initially = 1.38
mol NaOH initially = 2.90
mol NaOH after reacting = 2.90 - 1.38 = ? mols.