CaCO3 + 2HCl ==> H2O + CO2 + CaCl2
NaOH + HCl ==> H2O + NaCl
mols HCl initially = M x L = estimated 0.013 but you need a better number than this. All of the other numbers that follow are estimates, too.
mols excess HCl = M x L = estd 0.0027
mols HCl used to neutralize CaCO3 = 0.013-0.0027 = estd 0.010 mols.
mols CaCO3 = 0.010 mols HCl x 1 mols CaCO3/2 mol HCl = estd 0.005
Then g CaCO3 = mols CaCO3 x molar mass CaCO3 = ?
If you want to know percent CaCO3 it is
(g CaCO3/1.3188)*100 = ?
1.3188g of antacid is weighed and mixed with 75.00mL of excess 0.1746M HCl. The excess acid required 27.20mL of 0.09767M of NaOH for back titration. Calculate the amount of CaCO3 in the tablet.
1 answer