1.2048g sample of impure Na2CO3 is dissolved and allowed to react with a solution of CaCl2 resulting CaCO3 after precipitation, filtaration and drying was found to weight 1.0362g. calculate the percentage purity of Na2CO3

Answer 1

1.0326g CaCO3 x (molar mass Na2CO3/molar mass CaCO3) = grams Na2CO3.
% purity = (grams Na2CO3/mass sample)*100 = ?

Answer 2

51.43