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1.2048g sample of impure Na2CO3 is dissolved and allowed to react with a solution of CaCl2 resulting CaCO3 after precipitation, filtaration and drying was found to weight 1.0362g. calculate the percentage purity of Na2CO3

2 answers

1.0326g CaCO3 x (molar mass Na2CO3/molar mass CaCO3) = grams Na2CO3.
% purity = (grams Na2CO3/mass sample)*100 = ?
51.43
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