1. 1f 3(8) +5(8) =281

, what is the value of the real number x [leave answer in
exact form]?

1 answer

To solve this equation, we need to first simplify the expression:

1f(3(8) + 5(8)) = 281
1f(24 + 40) = 281
1f(64) = 281
\(f = \frac{281}{64}\)

So the value of the real number x is \( x = \frac{281}{64} \)