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1.14g of sodium bicarbonate (NaHCO3)is dissolved in 500 mL H2O. What is the Ph of the solution? Assume constant volume.

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I have been trying to work this out with no success - any help would be great - Thanks

Without deriving the equation, the formula for what you want is
(H^+) = sqrt(k1k2) or
pH = 1/2(pK1 + pK2)
The answer for NaHCO3 is about 8.3 or so.

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