1.104g of impure sample of NaNO2 was acidified and analysed using excess iodine ion. The reaction is 2HNO2+ 3H+-----2NO + 2H2O+I3- . Then I3- is titrated with 0.300M Na2S2O3.

Question

S2O3 2- + I3- ------ I- +S4O6 2-
if the titre volume is 29.25cm3, calculate the % of NaNO2 in the sample

Answer 1

I got 27.5% NaNO2 (w/w) ... post work if you get stuck.
NOTE => You do need 3I^- on reactant side of the initial equation and on the product side of the thiosulfate rxn in post.

Answer 2

I'm getting double of that percentage, where have I gone wrong

Answer 3

Neville how did you come about to your answer I need the procedure?

Answer 4

Can you kindly give an explanation for your answer

Answer 5

Give the procedure

Answer 6

I found 25.04 percent

Answer 7

54.85%