1 + 1/4 + (1.3)/(4.8) + (1.3.5)/(4.8.12)+...... = _____
11 answers
Expand (1-x/2)^(-1/2) using Maclaurin Series and set x=1 and see what happens.
m not getting the answer by dat way.....plz help
If you have done MacLaurin expansion, you should be able to expand the expression.
What answer did you get?
What answer did you get?
1/2^(1/2)
i got the same answer too
Oh, sorry, the expression I gave is not correct.
It should have read:
[1/(1-x/2)]^(-1/2)
which should expand to
1+1/4+1.3/(4.8)+1.3.5/(4.8.12)+...
It should have read:
[1/(1-x/2)]^(-1/2)
which should expand to
1+1/4+1.3/(4.8)+1.3.5/(4.8.12)+...
Please disregard the previous correction.
The original expression IS correct, as it says:
(1-x/2)^(-1/2) [note the negative sign of the exponent]
=sqrt[1/(1-x/2)]
and should expand to:
1+1/4+1.3/(4.8)+1.3.5/(4.8.12)+...
The original expression IS correct, as it says:
(1-x/2)^(-1/2) [note the negative sign of the exponent]
=sqrt[1/(1-x/2)]
and should expand to:
1+1/4+1.3/(4.8)+1.3.5/(4.8.12)+...
so watz d method?
and note that (1-x/2) means (1-(x/2)) by the priority of multiplication over addition.
thanx
You're welcome!