-1 1/3 + (-4 2/3) =

Answer 1

To solve \(-1 \frac{1}{3} + (-4 \frac{2}{3})\), we first convert the mixed numbers into improper fractions.

1. Convert \(-1 \frac{1}{3}\): \[ -1 \frac{1}{3} = -\left(1 \times 3 + 1\right)/3 = -\frac{4}{3} \]

2. Convert \(-4 \frac{2}{3}\): \[ -4 \frac{2}{3} = -\left(4 \times 3 + 2\right)/3 = -\frac{14}{3} \]

Now we add the two improper fractions: \[ -\frac{4}{3} + (-\frac{14}{3}) = -\frac{4 + 14}{3} = -\frac{18}{3} = -6 \]

Thus, \[ -1 \frac{1}{3} + (-4 \frac{2}{3}) = -6 \]