(1, 1)
(0, -1)
Write the equation of the line in slope-intercept form. (1 point)
y= _x+ (__)
11 answers
y = -x + 0
thats wrong
Apologies for the mistake. Let's correct it:
Given the two points (1, 1) and (0, -1), we can calculate the slope of the line using the formula:
m = (y2 - y1) / (x2 - x1)
Substitute the values:
m = (-1 - 1) / (0 - 1)
m = (-2) / (-1)
m = 2
Now that we have the slope, we can use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
Selecting the point (1, 1):
y - 1 = 2(x - 1)
Expand and simplify:
y - 1 = 2x - 2
y = 2x - 1
Therefore, the equation of the line in slope-intercept form is:
y = 2x - 1
Given the two points (1, 1) and (0, -1), we can calculate the slope of the line using the formula:
m = (y2 - y1) / (x2 - x1)
Substitute the values:
m = (-1 - 1) / (0 - 1)
m = (-2) / (-1)
m = 2
Now that we have the slope, we can use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
Selecting the point (1, 1):
y - 1 = 2(x - 1)
Expand and simplify:
y - 1 = 2x - 2
y = 2x - 1
Therefore, the equation of the line in slope-intercept form is:
y = 2x - 1
the 2 is right but the 1 isnt
Apologies for the oversight. Let's correct it.
Given the slope of 2 and the point (1, 1), we can use the point-slope form:
y - y1 = m(x - x1)
Substitute the values:
y - 1 = 2(x - 1)
Expand and simplify:
y - 1 = 2x - 2
y = 2x - 1
Therefore, the equation of the line in slope-intercept form is:
y = 2x - 1
Thank you for pointing that out.
Given the slope of 2 and the point (1, 1), we can use the point-slope form:
y - y1 = m(x - x1)
Substitute the values:
y - 1 = 2(x - 1)
Expand and simplify:
y - 1 = 2x - 2
y = 2x - 1
Therefore, the equation of the line in slope-intercept form is:
y = 2x - 1
Thank you for pointing that out.
y = 2x + (__)
To rewrite the equation in slope-intercept form y = mx + b, we know that the slope (m) is 2 from the given points. To find the y-intercept (b), we can substitute the coordinates of one of the points into the equation and solve for b.
Using point (1, 1):
1 = 2(1) + b
1 = 2 + b
b = -1
Therefore, the slope-intercept form of the equation is:
y = 2x - 1
Using point (1, 1):
1 = 2(1) + b
1 = 2 + b
b = -1
Therefore, the slope-intercept form of the equation is:
y = 2x - 1
this is the equation
y = 2x + (__)
y = 2x + (__)
My apologies for the oversight. Let's correct that.
Given the slope is 2 and the points (1,1) lies on the line, we can calculate the y-intercept (b) of the line by substituting the coordinates of the point into the equation y = mx + b.
Using the point (1, 1):
1 = 2(1) + b
1 = 2 + b
b = -1
Therefore, the equation of the line in slope-intercept form is:
y = 2x - 1
So, the equation is:
y = 2x - 1
Given the slope is 2 and the points (1,1) lies on the line, we can calculate the y-intercept (b) of the line by substituting the coordinates of the point into the equation y = mx + b.
Using the point (1, 1):
1 = 2(1) + b
1 = 2 + b
b = -1
Therefore, the equation of the line in slope-intercept form is:
y = 2x - 1
So, the equation is:
y = 2x - 1
y = 2x + -1
Yes, that is correct. The equation of the line based on the given points and slope is:
y = 2x - 1
Thank you for your patience and clarification.
y = 2x - 1
Thank you for your patience and clarification.
1 answer