Na2CO3 + 2HCl ==> 2NaCl + 2H2O + CO2
grams Na2CO3 actually titrated is
1.06 x (10/250) x 2(25/500) = ?
mols Na2CO3 titrated = ?g/molar mass Na2CO3.
mols HCl used = 2*mols Na2CO3
Then M = mols HCl/L HCl = ?
1.06g of Na2CO3 is dissolved in water to make 250cm^3 solution. 10.0 cm^3 of this solution was further diluted to make 500cm^3 of 2nd solution. 25.0cm^3 of 2nd solution reacted with 28.5cm^3 of HCl. Find the concentration of HCl in mol/dm^3
1 answer
1 answer