1.000 g of bronze was dissolved in the mixture of acids. The solution was transferred

Question

into 100 ml volumetric flask and filled to the mark. 10 ml aliquote of this solution was
transferred into another 100 ml flask and diluted to the mark. 10 ml of the resulting
solution was analysed to contain 1.1 mg of tin. Calculate the percentage of tin and
copper in the metal sample. (Content of other metals may be regarded neglible.)

Answer 1

You diluted it 10*10 times
so in the origiaal, there were 110mg of tin.

Percent Tin-.110/1 * 100=11percent
Precent Cu=89 percent