1.00 mL of a 0.0500 M sucrose solution is transferred to a 100 mL volumetric flask, and the flask brought up to volume. 5.00 mL are taken from the 100 mL volumetric flask and transferred to a 0.500 L flask, and it is brought up to volume. What is the resulting concentration of sucrose in the 0.500 L flask?

Answer 1

You have 1 x 0.0500 = 0.0500 mmoles or 5E-5 moles in the 100 mL flask. That is then diluted so the new concn is
5E-5M x (5.00 mL/500 mL) = 5E-7M

Answer 2

where did u get 500ml?