!00.0 grams of Na2SO4 reacts with 150.00 grams of Ba(NO3)2to form NaNO3 and BaSO4. How many grams of barium sulfate will form?
2 answers
please help i really need the help
This is a limiting reagent problem. I know because amounts are given for BOTH reactants.
mols Na2SO4 = grams/molar mass.
mols Ba(NO3)2 = grams/molar mass.
Convert mols Na2SO4 to mols of the product. Do the same for mols Ba(NO3)2 to the product. It is likely that these two numbers will not agree which means one of them must be wrong. The correct answer in limiting reagent problems is ALWAYS the smaller value. Use the smaller valuer and convert to grams of the product.
g BaSO4 = mols BaSO4 x molar mass BaSO4.
mols Na2SO4 = grams/molar mass.
mols Ba(NO3)2 = grams/molar mass.
Convert mols Na2SO4 to mols of the product. Do the same for mols Ba(NO3)2 to the product. It is likely that these two numbers will not agree which means one of them must be wrong. The correct answer in limiting reagent problems is ALWAYS the smaller value. Use the smaller valuer and convert to grams of the product.
g BaSO4 = mols BaSO4 x molar mass BaSO4.
1 answer