Use the freezing point depression formula.
dT = Kf*m
Substitute and solve for m = molality.
m = mols/kg solvent.
Substitute and solve for mols.
mols = grams/molar mass
You know mols and grams, solve for mola rmass.
0.959 g of a hydrocarbon is dissolved in 10.00g of benzene. The freezing point of the solution is 1.16C. Find the molecular mass of the hydrocarbon. Benzene has a Kf of 5.12 and a freezing points of 5.53 degrees C.
Not sure how to go about solving this problem? Thanks!
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